{"id":18184,"date":"2024-04-06T08:19:56","date_gmt":"2024-04-06T08:19:56","guid":{"rendered":"https:\/\/soicau4017.minhngocxoso.com\/?p=18184"},"modified":"2024-04-06T08:19:56","modified_gmt":"2024-04-06T08:19:56","slug":"huong-dan-choi-nuoi-khung-mien-bac-soi-cau-chuan-xac","status":"publish","type":"post","link":"https:\/\/thandongxoso.com\/huong-dan-choi-nuoi-khung-mien-bac-soi-cau-chuan-xac\/","title":{"rendered":"h\u01b0\u1edbng d\u1eabn ch\u01a1i nu\u00f4i khung mi\u1ec1n b\u1eafc soi c\u1ea7u chu\u1ea9n x\u00e1c"},"content":{"rendered":"
<\/p>\n\n\n
Kinh nghi\u1ec7m x\u1ed5 s\u1ed1 nu\u00f4i khung mi\u1ec1n b\u1eafc soi c\u1ea7u l\u00e0 m\u1ed9t trong nh\u1eefng g\u00ec quan tr\u1ecdng nh\u1ea5t \u0111\u1ec3 anh em chi\u1ebfn th\u1eafng ch\u1ee7 l\u00f4 . \u0110\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p c\u0169ng nh\u01b0 c\u00e1ch ch\u01a1i ph\u1ed5 bi\u1ebfn \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi t\u00ecm hi\u1ec3u v\u00e0 \u00e1p d\u1ee5ng. T\u00f9y v\u00e0o nh\u1eefng c\u00e1ch soi c\u1ea7u v\u00e0 ph\u01b0\u01a1ng ph\u00e1p b\u1eaft m\u00e0 ng\u01b0\u1eddi ch\u01a1i s\u1ebd l\u1ef1a ch\u1ecdn nh\u1eefng lo\u1ea1i l\u00f4 khung kh\u00e1c nhau. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 t\u1ed5ng h\u1ee3p nh\u1eefng lo\u1ea1i nu\u00f4i l\u00f4 khung b\u1ea5t b\u1ea1i m\u00e0 b\u1ea1n c\u00f3 th\u1ec3 tham kh\u1ea3o.<\/p>\n\n\n\n
L\u00f4 khung 2 ng\u00e0y l\u00e0 vi\u1ec7c nu\u00f4i l\u00f4 khung : L\u1ef1a ch\u1ecdn nh\u1eefng con l\u00f4 \u0111\u1eb9p nu\u00f4i trong kho\u1ea3ng 2 ng\u00e0y. <\/p>\n\n\n\n
C\u00e1c lo\u1ea1i l\u00f4 nu\u00f4i khung 2 ng\u00e0y ph\u1ed5 bi\u1ebfn nh\u1ea5t<\/strong><\/p>\n\n\n\n \u2013 B\u1ea1ch th\u1ee7 l\u00f4 khung nu\u00f4i 2 ng\u00e0y: T\u1ee9c l\u00e0 b\u1ea1n s\u1ebd l\u1ef1a ch\u1ecdn 1 con l\u00f4 duy nh\u1ea5t v\u00e0 nu\u00f4i l\u00f4 \u0111\u00f3 theo khung 2 ng\u00e0y. <\/p>\n\n\n\n \u2013 Song th\u1ee7 l\u00f4 khung 2 ng\u00e0y<\/strong> : C\u0169ng t\u01b0\u01a1ng t\u1ef1 nh\u01b0 b\u1ea1ch th\u1ee7 l\u00f4 khung 2 ng\u00e0y. Ng\u01b0\u1eddi ch\u01a1i s\u1ebd soi c\u1ea7u l\u00f4 v\u00e0 nu\u00f4i l\u00f4 khung trong v\u00f2ng 2 ng\u00e0y.<\/p>\n\n\n\n \u2013 L\u00f4 k\u00e9p nu\u00f4i khung 2 ng\u00e0y<\/strong> t\u1ee9c l\u00e0 b\u1ea1n l\u1ef1a ch\u1ecdn nh\u1eefng con l\u00f4 gi\u1ed1ng nhau. Nh\u01b0 (k\u00e9p b\u1eb1ng), ho\u1eb7c nh\u1eefng bi\u1ebfn th\u1ec3 c\u1ee7a l\u00f4 k\u00e9p (k\u00e9p \u00e2m, s\u00e1t k\u00e9p,..) . \u0110\u1ec3 nu\u00f4i trong kho\u1ea3ng th\u1eddi gian l\u00e0 2 ng\u00e0y.<\/p>\n\n\n\n Kinh nghi\u1ec7m v\u00e0o ti\u1ec1n l\u00f4 nu\u00f4i khung chu\u1ea9n nh\u1ea5t th\u01b0\u1eddng theo t\u1ec9 l\u1ec7 1: 2 v\u00e0 1:3, v\u1edbi nh\u1eefng m\u1ee9c n\u00e0y ng\u01b0\u1eddi ch\u01a1i s\u1ebd kh\u00f4ng m\u1ea5t qu\u00e1 nhi\u1ec1u v\u1ed1n m\u00e0 v\u1eabn \u0111\u1ea3m b\u1ea3o \u0111\u01b0\u1ee3c m\u1ee9c l\u00e3i cao n\u1ebfu tr\u00fang l\u00f4.<\/p>\n\n\n\n \u2013 V\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 khung t\u1ec9 l\u1ec7 1:2 nh\u01b0 sau: N\u1ebfu ng\u00e0y \u0111\u1ea7u ti\u00ean b\u1ea1n \u0111\u00e1nh 10 \u0111i\u1ec3m cho 1 con l\u00f4 (1 \u0111i\u1ec3m = 23.000 \u0111\u1ed3ng), th\u00ec ng\u00e0y th\u1ee9 2 b\u1ea1n s\u1ebd \u0111\u00e1nh 20 \u0111i\u1ec3m cho con l\u00f4 n\u00e0y, n\u1ebfu l\u00e0 \u0111\u00e1nh song th\u1ee7 th\u1ee7 th\u00ec b\u1ea1n c\u00f3 th\u1ec3 \u0111\u00e1nh m\u1ed7i con 10 \u0111i\u1ec3m ho\u1eb7c \u0111\u00e1nh nhi\u1ec1u h\u01a1n t\u00f9y v\u00e0o ngu\u1ed3n t\u00e0i ch\u00ednh c\u1ee7a b\u1ea1n.<\/p>\n\n\n\n \u2013 V\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 khung t\u1ec9 l\u1ec7 1:3 nh\u01b0 sau: Ng\u00e0y \u0111\u1ea7u ti\u00ean v\u00e0o ti\u1ec1n 10 \u0111i\u1ec3m cho 1 con, sang t\u1edbi ng\u00e0y th\u1ee9 2 b\u1ea1n s\u1ebd \u0111\u00e1nh 30 \u0111i\u1ec3m cho 1 con. Nh\u01b0 v\u1eady n\u1ebfu b\u1ea1n \u0111\u00e1nh song th\u1ee7 th\u00ec s\u1ed1 ti\u1ec1n b\u1ea1n s\u1ebd v\u00e0o g\u1ea5p \u0111\u00f4i v\u1edbi h\u01b0\u1edbng d\u1eabn ph\u00eda tr\u00ean.<\/p>\n\n\n\n Nu\u00f4i l\u00f4 khung ba ng\u00e0y t\u1ee9c l\u00e0 b\u1ea1n s\u1ebd soi c\u1ea7u l\u1ef1a ch\u1ecdn nh\u1eefng con s\u1ed1 \u0111\u1eb9p. V\u00e0 \u0111\u00e1nh nh\u1eefng con l\u00f4 \u0111\u00f3 trong kho\u1ea3ng th\u1eddi gian max 3 ng\u00e0y.<\/p>\n\n\n <\/p>\n\n\n L\u00f4 nu\u00f4i khung max 3 ng\u00e0y c\u0169ng t\u01b0\u01a1ng t\u1ef1 nh\u01b0 khung 2 ng\u00e0y, c\u00f3 nh\u1eefng lo\u1ea1i ph\u1ed5 bi\u1ebfn nh\u01b0: <\/p>\n\n\n\n \u2013 B\u1ea1ch th\u1ee7 khung 3 ng\u00e0y l\u00e0 nu\u00f4i 1 con l\u00f4 trong 3 ng\u00e0y.<\/p>\n\n\n\n \u2013 Song th\u1ee7 l\u00f4 khung 3 ng\u00e0y t\u1ee9c l\u00e0 nu\u00f4i 1 c\u1eb7p l\u00f4 v\u1edbi th\u1eddi gian l\u00e0 3 ng\u00e0y.<\/p>\n\n\n\n \u2013 L\u00f4 k\u00e9p khung 3 ng\u00e0y v\u00e0 nu\u00f4i \u0111\u1ea7u \u0111u\u00f4i khung 3 ng\u00e0y<\/p>\n\n\n\n \u2013 V\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 khung 3 ng\u00e0y theo t\u1ec9 l\u1ec7 1:2:4, t\u1ee9c l\u00e0:<\/p>\n\n\n\n Ng\u00e0y 1 v\u00e0o 10 \u0111i\u1ec3m l\u00f4, n\u1ebfu \u0111\u00e1nh 1 con th\u00ec s\u1ed1 ti\u1ec1n s\u1ebd l\u00e0 230.000 \u0111\u1ed3ng.<\/p>\n\n\n\n Ng\u00e0y 2 v\u00e0o 20 \u0111i\u1ec3m l\u00f4, s\u1ed1 ti\u1ec1n nu\u00f4i l\u00f4 ng\u00e0y th\u1ee9 2 s\u1ebd l\u00e0 460.000 \u0111\u1ed3ng. N\u1ebfu th\u1eafng trong ng\u00e0y th\u00ec b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c s\u1ed1 ti\u1ec1n l\u00e0 1.600.000 (t\u00ednh theo t\u1ec9 l\u1ec7 1:80, m\u1ed9t s\u1ed1 n\u01a1i c\u00f3 th\u1ec3 cao ho\u1eb7c th\u1ea5p h\u01a1n), tr\u1eeb \u0111i s\u1ed1 ti\u1ec1n v\u1ed1n 2 ng\u00e0y b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c ti\u1ec1n l\u00e3i l\u00e0 680.000 \u0111\u1ed3ng.<\/p>\n\n\n\n Ng\u00e0y 3 v\u00e0o 40 \u0111i\u1ec3m l\u00f4, t\u01b0\u01a1ng \u1ee9ng v\u1edbi 920.000 \u0111\u1ed3ng, n\u1ebfu th\u1eafng s\u1ed1 ti\u1ec1n l\u00e3i b\u1ea1n nh\u1eadn \u0111\u01b0\u1ee3c l\u00ean t\u1edbi 1.280.000 \u0111\u1ed3ng.<\/p>\n\n\n\n \u2013 V\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 theo t\u1ec9 l\u1ec7 1:3:6<\/p>\n\n\n\n Ngo\u00e0i vi\u1ec7c \u0111\u00e1nh \u0111i\u1ec3m, ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ee7 \u0111\u1ed9ng b\u1eb1ng c\u00e1ch b\u1ecf ra m\u1ed9t s\u1ed1 ti\u1ec1n v\u1ed1n nh\u1ea5t \u0111\u1ecbnh \u0111\u1ec3 nu\u00f4i l\u00f4, chia s\u1ed1 ti\u1ec1n n\u00e0y th\u00e0nh 10 ph\u1ea7n v\u00e0 \u0111\u00e1nh nh\u01b0 sau:<\/p>\n\n\n\n Ng\u00e0y 1 nu\u00f4i l\u00f4 v\u1edbi s\u1ed1 ti\u1ec1n l\u00e0 1\/10 ti\u1ec1n v\u1ed1n.<\/p>\n\n\n\n Ng\u00e0y 2 nu\u00f4i l\u00f4 v\u1edbi s\u1ed1 ti\u1ec1n l\u00e0 3\/10 ti\u1ec1n v\u1ed1n.<\/p>\n\n\n\n Ng\u00e0y 3 nu\u00f4i l\u00f4 v\u1edbi s\u1ed1 ti\u1ec1n c\u00f2n l\u1ea1i \u1ee9ng v\u1edbi 6\/10 ti\u1ec1n v\u1ed1n.<\/p>\n\n\n\n \u2013 V\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 khung 3 ng\u00e0y theo t\u1ec9 l\u1ec7 1:3:10, t\u1ee9c l\u00e0:<\/p>\n\n\n\n Ng\u00e0y 1 \u0111\u00e1nh 10 \u0111i\u1ec3m l\u00f4<\/p>\n\n\n\n Ng\u00e0y 2 \u0111\u00e1nh 30 \u0111i\u1ec3m l\u00f4<\/p>\n\n\n\n Ng\u00e0y 3 \u0111\u00e1nh 100 \u0111i\u1ec3m l\u00f4<\/p>\n\n\n\n C\u00e1ch nu\u00f4i l\u00f4 khung n\u00e0y cho m\u1ee9c l\u00e3i thu \u0111\u01b0\u1ee3c kh\u00e1 cao, tuy nhi\u00ean ng\u01b0\u1eddi ch\u01a1i c\u0169ng c\u1ea7n ch\u00fa \u00fd t\u1edbi ngu\u1ed3n t\u00e0i ch\u00ednh c\u1ee7a m\u00ecnh \u0111\u1ec3 l\u1ef1a ch\u1ecdn t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n ph\u00f9 h\u1ee3p.<\/p>\n\n\n\n C\u00f3 hai c\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i khung l\u00f4 trong v\u00f2ng 5 ng\u00e0y. Anh ch\u1ecb em tham kh\u1ea3o v\u00e0 v\u00e0o ti\u1ec1n h\u1ee3p l\u00fd nh\u00e9.<\/p>\n\n\n\n \u2013 V\u00e0o ti\u1ec1n theo t\u1ec9 l\u1ec7 1:2:4:8:20, c\u00e1ch ti\u1ebfn h\u00e0nh nh\u01b0 sau:<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 nh\u1ea5t \u0111\u00e1nh 10 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 hai \u0111\u00e1nh 20 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 3 \u0111\u00e1nh 40 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 4 \u0111\u00e1nh 80 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 5 \u0111\u00e1nh 200 \u0111i\u1ec3m.<\/p>\n\n\n\n Nh\u01b0 v\u1eady sau 5 ng\u00e0y ng\u01b0\u1eddi ch\u01a1i \u0111\u00e1nh h\u1ebft 350 \u0111i\u1ec3m. N\u1ebfu 4 ng\u00e0y \u0111\u1ea7u l\u00f4 kh\u00f4ng ra v\u00e0 xu\u1ea5t hi\u1ec7n v\u00e0o ng\u00e0y 5 th\u00ec b\u1ea1n s\u1ebd thu \u0111\u01b0\u1ee3c s\u1ed1 ti\u1ec1n l\u00e0 7.950.000 \u0111\u1ed3ng. <\/p>\n\n\n\n \u2013 V\u00e0o ti\u1ec1n theo t\u1ec9 l\u1ec7 1:1:2:3:5:8<\/p>\n\n\n\n C\u00e1ch v\u00e0o ti\u1ec1n n\u00e0y d\u1ef1a theo chu\u1ed7i d\u00e3y s\u1ed1 v\u00e0ng Fibonacci l\u00e0 1 \u2013 1 \u2013 2 \u2013 3 \u2013 5 \u2013 8 \u2013 13 \u2013 21- \u2026<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 nh\u1ea5t \u0111\u00e1nh 10 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 hai \u0111\u00e1nh 20 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 3 \u0111\u00e1nh 30 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 4 \u0111\u00e1nh 50 \u0111i\u1ec3m.<\/p>\n\n\n\n Ng\u00e0y th\u1ee9 5 \u0111\u00e1nh 80 \u0111i\u1ec3m.<\/p>\n\n\n\n V\u1edbi c\u00e1ch n\u00e0y ng\u01b0\u1eddi ch\u01a1i l\u01b0u \u00fd nh\u01b0 sau:<\/p>\n\n\n\n N\u1ebfu tr\u00fang ng\u00e0y \u0111\u1ea7u ti\u00ean th\u00ec n\u00ean ngh\u1ec9 c\u1ea7u v\u00e0 b\u1eaft \u0111\u1ea7u nu\u00f4i s\u1ed1 m\u1edbi.<\/p>\n\n\n\n N\u1ebfu tr\u00fang t\u1eeb ng\u00e0y th\u1ee9 2 tr\u1edf \u0111i th\u00ec quay l\u1ea1i t\u1ec9 l\u1ec7 c\u1ee7a ng\u00e0y tr\u01b0\u1edbc \u0111\u00f3, c\u00f2n n\u1ebfu tr\u01b0\u1ee3t th\u00ec ti\u1ebfp t\u1ee5c v\u00e0o ti\u1ec1n theo t\u1ec9 l\u1ec7 ban \u0111\u1ea7u.<\/p>\n\n\n\n T\u1ed5ng k\u1ebft: Tr\u00ean \u0111\u00e2y l\u00e0 to\u00e0n b\u1ed9 ph\u00e2n t\u00edch kinh nghi\u1ec7m v\u00e0 ph\u01b0\u01a1ng ph\u00e1p c\u00f9ng c\u00e1ch v\u00e0o ti\u1ec1n. H\u01b0\u1edbng d\u1eabn ch\u01a1i nu\u00f4i khung mi\u1ec1n b\u1eafc soi c\u1ea7u chu\u1ea9n x\u00e1c g\u1eedi \u0111\u1ebfn anh ch\u1ecb em. Ch\u00fac anh ch\u1ecb em c\u00f3 nh\u1eefng ph\u00fat gi\u00e2y online vui v\u1ebb v\u00e0 may m\u1eafn ph\u00e1t t\u00e0i.<\/p>\n\n\n <\/p>\r\n\r\nC\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 khung soi c\u1ea7u 2 ng\u00e0y hi\u1ec7u qu\u1ea3<\/strong><\/h3>\n\n\n\n
2. Nu\u00f4i khung mi\u1ec1n b\u1eafc 3 ng\u00e0y soi c\u1ea7u <\/strong><\/h2>\n\n\n\n
Nu\u00f4i l\u00f4 khung max 3 ng\u00e0y g\u1ed3m nh\u1eefng lo\u1ea1i n\u00e0o?<\/strong><\/h3>\n\n\n\n
Kinh nghi\u1ec7m v\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 khung 3 ng\u00e0y<\/strong><\/h3>\n\n\n\n
3. V\u00e0o ti\u1ec1n nu\u00f4i khung mi\u1ec1n b\u1eafc soi c\u1ea7u 5 ng\u00e0y r\u1ed3ng b\u1ea1ch kim chu\u1ea9n nh\u1ea5t<\/strong><\/h3>\n\n\n\n
soi c\u1ea7u cao c\u1ea5p<\/span><\/h3>\r\n